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4x^2-48x-25=0
a = 4; b = -48; c = -25;
Δ = b2-4ac
Δ = -482-4·4·(-25)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2704}=52$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-52}{2*4}=\frac{-4}{8} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+52}{2*4}=\frac{100}{8} =12+1/2 $
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